(4^2x)(6^x)=1728

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Solution for (4^2x)(6^x)=1728 equation: 



(4^2x)(6^x)=1728

We move all terms to the left:

(4^2x)(6^x)-(1728)=0

We move all terms containing x to the left, all other terms to the right

4^2x6^x=1728

x=1728/1

x=1728

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